Check ith Bit of a Number is Set or Not Using Bit Manipulation

Logical AND (&) of 2 different bit patterns will give 1 only if both bits have 1. to check ith bit of a number is set or not first Right Shift (<<) 1 to ith position,  then AND (&) both the number,  if both the bit patterns have 1 at the ith place, the result will be 0.

package org.wesome.dsalgo;

public class CheckIthBitSet {
    public static boolean checkIthBitSet(int number, int check) {
        int rightShift = (1 << check);
        System.out.println(number + " In binary will be " + Integer.toBinaryString(number) + ", 1 right shift up to " + check + " position In binary will be " + Integer.toBinaryString(rightShift));
        int result = (number & check);
        boolean ithBitSet = (result > 0);
        System.out.println("result is " + result + ", " + check + "th bit of " + number + " is set " + ithBitSet);
        return ithBitSet;
    }
}

package org.wesome.dsalgo;

import org.junit.jupiter.api.Assertions;
import org.junit.jupiter.api.Test;

public class CheckIthBitSetTest {

    @Test
    void checkIthBitSetTest1() {
        Assertions.assertFalse(CheckIthBitSet.checkIthBitSet(2, 1));
    }

    @Test
    void checkIthBitSetTest2() {
        Assertions.assertTrue(CheckIthBitSet.checkIthBitSet(10, 3));
    }

    @Test
    void checkIthBitSetTest3() {
        Assertions.assertTrue(CheckIthBitSet.checkIthBitSet(20, 5));
    }
}

plugins {
    id 'java'
}

group = 'org.wesome'
version = '0.0.1-SNAPSHOT'
sourceCompatibility = JavaVersion.VERSION_1_8

configurations {
    compileOnly {
        extendsFrom annotationProcessor
    }
}

repositories {
    mavenCentral()
}

dependencies {
    testImplementation 'org.junit.jupiter:junit-jupiter:5.6.2'
}

test {
    useJUnitPlatform()
}